Improvement scores for identical twins taught music recognition by two techniques

Description

Data for Exercise 7.59

Usage

Music

Format

A data frame with 12 observations on the following 3 variables.

Method1

a numeric vector

Method2

a numeric vector

differ

a numeric vector

Source

Kitchens, L. J. (2003) Basic Statistics and Data Analysis. Duxbury

Examples

str(Music)
attach(Music)
qqnorm(differ)
qqline(differ)
shapiro.test(differ)
t.test(Method1,Method2,paired=TRUE)
detach(Music)

Results

R version 3.3.1 (2016-06-21) -- "Bug in Your Hair"
Copyright (C) 2016 The R Foundation for Statistical Computing
Platform: x86_64-pc-linux-gnu (64-bit)

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> library(BSDA)
Loading required package: e1071
Loading required package: lattice

Attaching package: 'BSDA'

The following object is masked from 'package:datasets':

    Orange

> png(filename="/home/ddbj/snapshot/RGM3/R_CC/result/BSDA/Music.Rd_%03d_medium.png", width=480, height=480)
> ### Name: Music
> ### Title: Improvement scores for identical twins taught music recognition
> ###   by two techniques
> ### Aliases: Music
> ### Keywords: datasets
> 
> ### ** Examples
> 
> str(Music)
'data.frame':	12 obs. of  3 variables:
 $ Method1: int  7 4 6 1 5 1 6 3 4 6 ...
 $ Method2: int  2 4 3 2 3 4 2 4 4 3 ...
 $ differ : int  5 0 3 -1 2 -3 4 -1 0 3 ...
> attach(Music)
> qqnorm(differ)
> qqline(differ)
> shapiro.test(differ)

	Shapiro-Wilk normality test

data:  differ
W = 0.96631, p-value = 0.8685

> t.test(Method1,Method2,paired=TRUE)

	Paired t-test

data:  Method1 and Method2
t = 1.5947, df = 11, p-value = 0.1391
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
 -0.411863  2.578530
sample estimates:
mean of the differences 
               1.083333 

> detach(Music)
> 
> 
> 
> 
> 
> dev.off()
null device 
          1 
>