Last data update: 2014.03.03

R: Data on Simsbury Marriages
E1.18R Documentation

Data on Simsbury Marriages

Description

The E1.18 data frame has 8 rows and 3 columns with data on the number of marriages (ma) that occurred between residents of each of 8 annular zones and residents of Simsbury, Connecticut, for the period 1930–39. The number of residents of each zone is given as pop and the midpoint of distance between Simsbury and the band is given as d.

Usage

data(E1.18)

Format

This data frame contains the following columns:

d

a numeric vector, distance between Simsbury and midpoint of annular zone.

pop

a numeric vector, population of annular zone.

ma

a numeric vector, number of marriages.

Source

Dacey (1983, ch 4) from Ellsworth (1948).

Examples

data(E1.18)
summary(E1.18)

Results


R version 3.3.1 (2016-06-21) -- "Bug in Your Hair"
Copyright (C) 2016 The R Foundation for Statistical Computing
Platform: x86_64-pc-linux-gnu (64-bit)

R is free software and comes with ABSOLUTELY NO WARRANTY.
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Type 'license()' or 'licence()' for distribution details.

R is a collaborative project with many contributors.
Type 'contributors()' for more information and
'citation()' on how to cite R or R packages in publications.

Type 'demo()' for some demos, 'help()' for on-line help, or
'help.start()' for an HTML browser interface to help.
Type 'q()' to quit R.

> library(SenSrivastava)
> png(filename="/home/ddbj/snapshot/RGM3/R_CC/result/SenSrivastava/E1.18.Rd_%03d_medium.png", width=480, height=480)
> ### Name: E1.18
> ### Title: Data on Simsbury Marriages
> ### Aliases: E1.18
> ### Keywords: datasets
> 
> ### ** Examples
> 
> data(E1.18)
> summary(E1.18)
       d             pop               ma       
 Min.   : 6.0   Min.   :  2583   Min.   : 4.00  
 1st Qu.: 9.5   1st Qu.:  4535   1st Qu.: 7.00  
 Median :13.0   Median : 27309   Median :12.00  
 Mean   :13.0   Mean   : 49784   Mean   :16.88  
 3rd Qu.:16.5   3rd Qu.: 70352   3rd Qu.:20.00  
 Max.   :20.0   Max.   :175458   Max.   :49.00  
> 
> 
> 
> 
> 
> dev.off()
null device 
          1 
>